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Special relativity: from clock operations to electrodynamics: §9 · charge and current

Zur Elektrodynamik bewegter Körper

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§9 · charge and current

Neutrality and current belong to a frame

How can a neutral current acquire charge density?

ρ′=γ(ρ−vJxc2),Jx′=γ(Jx−vρ)\rho'=\gamma\left(\rho-\frac{vJ_x}{c^2}\right),\qquad J_x'=\gamma(J_x-v\rho)

The primed charge density is gamma times rho minus v times the current along x over c squared; the primed current along x is gamma times the current along x minus v times rho.

The current components across the motion, JyJ_y and JzJ_z, are unchanged. For a neutral wire, ρ=0\rho = 0, carrying current JxJ_x, the new density is ρ′=−γvJx/c2\rho' = -\gamma vJ_x/c^2, which is not zero for any v≠0v \ne 0. To see why, transform each kind of charge on its own: the positive ions and the moving electrons have different velocities, so their densities change by different factors.

Charge is conserved in every frame: density and current together obey the continuity equation. The total charge of one body is the same in both frames when each frame adds up the charge at one of its own instants. A fixed box of space is a different comparison, because charge flows through its walls. The charge-and-current laboratory compares the densities and the total charge of a body.

Return to how a neutral wire carries charge density in another frame. (included in this file)

Charge density depends on the frame

Modern teaching equation, not the equation as printed.

ρ′=γ (ρ−v Jxc2)\rho' = \gamma\,\left(\rho - \frac{v\,J_x}{c^{2}}\right)

The charge density in the moving system is the Lorentz factor times the stationary charge density minus the speed of the moving system times the current density along x over the speed of light squared.

A current in one system contributes to the charge density in the other. A wire that is neutral in the stationary system but carries a current is not neutral in the moving system.

The current along the motion depends on the frame

Modern teaching equation, not the equation as printed.

Jx′=γ (Jx−v ρ)J_x' = \gamma\,\left(J_x - v\,\rho\right)

Primed longitudinal current is gamma times J x minus v rho.

Charge at rest in one system is a current in the other: charge density times the speed of the system.

Assumptions

  • Charge and current are spread through a real body, and the new observer moves along x.
  • When total charge is compared between frames, it is the charge of the same isolated body.

Limits

  • Charge density is not total charge: a density can change between frames while the body’s charge stays fixed.
  • In a neutral wire the positive and negative charges move at different speeds, so there is no single velocity of the charge.

Foundations included in this file

Adding and averaging

What does an average keep, and what does it lose?

Four jars hold 3, 1, 1 and 3 marbles. Pour them together and there are 8. Share the 8 equally between the four jars and each holds 2. Two is the average, although no jar held 2 to begin with.

The average keeps the total and the count and nothing else, so 3, 1, 1, 3 and 2, 2, 2, 2 have the same average. Listing every value twice doubles both the total and the count, and the average stays at 2.

Worked example: Three mornings with the same average

  1. One morning the four jars hold 3, 1, 1 and 3 marbles. Add them: 8. Divide by the four jars: an average of 2.
  2. Another morning they hold 8, 0, 0 and 0. Add them: 8 again. Divide by four: 2 again, and now three jars are empty.
  3. A third morning every jar holds 2, which is the average itself. Add them: 8. Divide by four: 2.
  4. Write any of those three lists out twice over. The total doubles to 16 and the count doubles to 8 jars, and 16 divided by 8 is still 2.
  5. Four descriptions and one average. It keeps the total and the count, and the differences between the mornings are what it leaves behind.

Where this lesson stops

An average is the total shared equally among the observations, and two very different lists can have the same one.

Return to the chapter

Counting what crosses a boundary

If particles keep crossing the edges of a region, what decides whether it fills up or empties?

Take a short stretch of a tube. If more particles cross into it than cross out, the number inside goes up. The flux J counts the net number crossing a surface per unit area and per second, with rightward crossings positive; the concentration c counts particles per unit volume. They measure different things, and the equation below connects them.

∂c∂t=−∂J∂x\frac{\partial c}{\partial t}=-\frac{\partial J}{\partial x}

The rate at which the concentration changes equals minus the rate at which the flux changes along x.

The minus sign is the bookkeeping. If the rightward flux is larger at the right end of the stretch than at the left, more particles leave on the right than arrive on the left, and the concentration falls.

Worked example: Seven particles in, five out

  1. In one second, 7 particles cross into the stretch and 5 cross out. The count inside rises by 2.
  2. Next second, 5 cross in and 5 cross out. The count is unchanged, although 10 particles crossed.

Where this lesson stops

The contents change by the net crossing. A steady count does not mean the particles have stopped, only that as many leave as arrive.

This lesson builds on

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Static laboratory examples

sr-12: a built-in worked result

Static host-calculated example, not a running experiment or an observation. Canonical units and owner-supplied statuses are retained. Open sr-12 online

Build-time scalar readouts
QuantityValueUnitStatus
chargeDensityStationary0C/m^3value
chargeDensityMoving-2.5017307139861402e-9C/m^3value
fourCurrentInvariant-1A^2/m^4value
fourCurrentInvariantNormalized-1.1126500560536185e-171value
lorentzFactor1.251value
continuityResidualStationary0A/m^3value
continuityResidualMoving0A/m^3value
loopLegChargePositive-2.0013845711889123e-9Cvalue
loopLegChargeNegative2.0013845711889123e-9Cvalue
loopTotalCharge0Cvalue
sphereTotalChargeStationary0Cvalue
sphereTotalChargeMoving0Cvalue

2 array outputs are not reproduced. This table does not claim to reproduce the interactive plot.

Settings (canonical units)

boost
179875474.79999998
carrierVelocityX
149896229
carrierVelocityY
0
carrierVelocityZ
0
chargeDensity
0
currentDensityX
1
currentDensityY
0
currentDensityZ
0
descriptionFrame
stationary
loopCurrent
1
loopLengthX
1
loopLengthY
0.5
mode
neutral-conductor
pulseAmplitude
1
pulseWidth
1
sphereCharge
4.1887902047863905
sphereRadius
1
unitLayer
si

Evaluator: source:sha256:e962d3f47d7f549ca2312d7c2adfd74225289385c0457dc806d0ca8f3c4b14c3

Source references

  1. A. Einstein, Zur Elektrodynamik bewegter Körper. Annalen der Physik (4), 17, 891–921 (1905).