Mass–Energy · System Boundaries & Empirical Checks

System boundaries
and the energy ledger.

When energy leaves a body as radiation, which system loses mass, and which does not? Drag a thermodynamic boundary around the components and inspect what energy crosses it.

Read the explanatory preview and its scope →

System boundary energy ledger · reference model, host calculation

ME-03: System-boundary energy ledger with cited energy-source cards

Energy that leaves a body takes mass with it. Draw the line around the body and its light together, and nothing is lost.

Notation:
Presets:
Thermodynamic Boundary & FluxSelected Boundary: body-alone (escapes)Combined Isolated SystemSource BodyΔm = -L/c²Radiation Escapes (+L)Boundary Energy LedgerActive Boundary: body-aloneEnergy change ΔE: -1 JMass change Δm: -1.1127e-17 kgCase Study: Radium-226 Alpha DecayEnergy: 4.871 MeV per decayMass Change: 0.0052292 u/decay (5.229 mg/mol)Matter Crosses: No (Closed system)Closed but not isolated (energy leaves)

Case Study Facts: Radium-226 Alpha Decay

Citation: NuDat 3.0 / Evaluated Nuclear Structure Data File (ENSDF), Brookhaven National Laboratory (226Ra Q-alpha = 4.871 MeV).

1. System before:
Radium-226 nucleus at rest
2. System after:
Radon-222 nucleus and alpha particle after heat emission
3. Matter crosses boundary:
No (Closed system: The radon-222 nucleus and the alpha particle both stay inside the boundary.)
4. Radiation disposition:
escapes (The decay energy leaves as heat.)
5. Reference frame:
Rest frame of parent nucleus
6. Energy figure:
4.871 MeV (decay-energy-per-event)
7. Closed but not isolated: Nothing material crosses this boundary, but the system is not isolated: energy still enters or leaves it.
Formalism & Mode
Mode:
System Boundary & Formalism
System boundary (objects included):
Energy retained or released:
Cited Energy-Source Case Studies
Select case study:

Predict before inspecting the sealed box:

A sealed box holds a battery-powered lamp and a mirror. When the lamp lights up inside, does the box's total mass change?

Show the reference code & kernel bindings

Reference evaluator: src/physics/reference/massEnergy.ts

// evaluateBoundaryLedger
const bodyDeltaM = -emittedEnergy / (c * c);
const sysDeltaM = disposition === "retained" ? inputEnergy / (c * c) : 0;

// evaluateFourMomentum
const mSquared = (totalEnergy / c)^2 - p^2;
const invariantMass = Math.sqrt(Math.max(0, mSquared));

Not modeled in this ideal reference calculation:

gravitational weighing · wall stresses, or external work beyond declared inputs · nuclear and chemical mechanisms beyond cited energies · heat losses not declared · neutrino and solar-wind mass loss · the practical measurability of tiny mass changes · the 1905 argument's premises (inherited, not re-derived) · non-inertial or accelerated frames

The physics of the boundary

Three thermodynamic boundaries

Einstein concludes that if a body gives off the energy L in the form of radiation, its mass diminishes by L/V² (or in modern notation L/c²):

Δm=Lc2\Delta m = -\frac{L}{c^2}

The total energy of an isolated system is strictly conserved. If the boundary is drawn around the emitting body and the radiation together inside a sealed container, no energy escapes, and the total mass of the enclosure remains completely unchanged:

ΔEisolated=0    Δmisolated=0\Delta E_{\text{isolated}} = 0 \implies \Delta m_{\text{isolated}} = 0

Closed systems versus isolated systems

A system is closed if no matter crosses its boundary. It is isolated only if neither matter nor energy crosses its boundary. A radioactive radium salt sealed in an ampoule exchanges heat with its surroundings without losing matter; its mass decreases only as that heat leaves the container.

Modern four-momentum invariant mass

In modern relativistic mechanics, the invariant mass m of any system of particles or photons is the Lorentz norm of its total four-momentum P^μ = (E/c, p):

m2c2=PμPμ=(Ec)2p2m^2 c^2 = P^\mu P_\mu = \left(\frac{E}{c}\right)^2 - \|\mathbf{p}\|^2

While a single light pulse has |p| = E/c and is therefore massless (m = 0), two equal and opposite light pulses have total momentum p = 0 and carry a nonzero system invariant mass:

mtwo pulses=Lc2m_{\text{two pulses}} = \frac{L}{c^2}