Special relativity · The opening asymmetry

The same relative motion,
two accounts of one current.

Why does moving the magnet instead of the conductor create an explanatory asymmetry, and how does the transformation remove it? Both descriptions are internally coherent. They agree on what is measured to first order in v/c.

The four-paper catalogue (source edition in preparation) →

SR-02 · Magnet and conductor

Magnet and conductor

Ideal model, host calculation

The same relative motion of magnet and conductor can be told two ways; nature does not care which body we call at rest.

In the magnet's rest frame the charges in the moving conductor feel q(v × B). In the conductor's rest frame those charges feel qE', and E' is the transform of the magnet's field. The two electromotive forces along a path across the motion differ by the factor gamma.

Choose which body is described as moving, type a speed, and inspect both accounts of the same current. No dragging is required. The ether-plus-local-time account is not declared refuted; at the speeds of real apparatus it agrees to first order in v/c.

Set the description
Mode
Description frame

Accepted snapshot

Both descriptions of the same event. The electromotive-force ratio names the simultaneity slice that fixed the path.
B (magnet rest)1 T
E (magnet rest)0 V/m
E′_y (conductor rest)-10 V/m
Force on q (magnet rest)-1.6022e-18 N
Force on q (conductor rest)-1.6022e-18 N
Electromotive force, magnet rest1 V
Electromotive force, conductor rest1 V (slice: magnet rest K)
Excess γ − 15.5633e-16
Endpoint offset0 s
Circuit currentCurrent in a real circuit is not modeled; SR-02 has no circuit.

Not modeled: conductor resistance and induced currents; self-inductance; magnetization dynamics and extended-magnet fields beyond the ideal dipole; time-varying flux of extended circuits; edge fields; radiation; unipolar machines; electromotive-force comparison across frames for a path with a component along the direction of motion, which needs a declared simultaneity slice this model does not supply.

Open the two descriptions

A path across the motion is comparable

An electromotive force is work per unit charge along a stated path, not a field component. The default segment lies along ŷ, across a boost along x̂, so the endpoint events have Δx = 0. They are simultaneous in both frames, the length is unchanged, and the ratio of the two electromotive forces is exactly γ.

E=vB,E=γvB,E=γ(v×B)\mathcal{E}=vB\ell,\qquad \mathcal{E}'=\gamma vB\ell,\qquad \mathbf{E}'_\perp=\gamma(\mathbf{v}\times\mathbf{B})_\perp

At 10 m/s with B = 1 T and ℓ = 0.1 m the magnet-frame value is 1 V. The excess γ − 1 is 5.563×10⁻¹⁶ from the cancellation-free form; a float64 evaluation of γ − 1 is not that number. At 0.6c the ratio is 1.25. Those two electromotive forces are not the same number, and they are not supposed to be: the correct comparison is the transformation law. Lorentz's ether plus local time produces the same first-order formulae and is not declared refuted here.