Special relativity · Electrodynamics §8

A packet of light does not transform
like a rigid material body.

How do the energy and volume of a bounded light complex transform between frames?

Read §8 of the 1905 relativity paper →

SR-10 · The finite light complex

The finite light complex

Ideal model, host calculation

A bounded packet of light transforms in energy by q = γ(1 − β cos φ) and in volume by 1/q. Neither factor is the material contraction 1/γ.

Einstein's printed volume of the complex is V′/V = 1/q, not 1/γ. Energy and frequency follow q. For receding light along the axis at β = 0.6, q = 1/2: energy halves and volume doubles. A rigid rod of the same rest volume would contract to 0.8.

A bounded pulse of light does not transform like a solid rod. Energy follows q = γ(1 − β cos φ). Volume follows 1/q. The planted negative “it contracts like a rod” is tested at φ = 90° in K, where q = γ and 1/γ differ by γ², and along the axis. At cos φ = β the energy factor equals 1/γ and cannot catch that mistake.

Set observer speed and packet parameters
Relativistic Light Complex Transformation (Einstein 1905 §8)Stationary Frame KSpherical light complex · E = 1.00 J · V = 1.00xyφ = 0.0°Moving Frame k (β = 0.60c)Physical complex · E′ = 0.50 J · V′ = 2.00x′y′v = 0.60cRod: 1/γφ′ = 0.0°
Energy ratio E′/E (q)
0.500000
γ(1 − β cos φ) = ν′/ν
Volume ratio V′/V (1/q)
2.000000
1 / [γ(1 − β cos φ)]
Energy density ratio u′/u
0.250000
q² = (A′/A)²
Lorentz factor γ
1.250000
1 / √(1 − β²)
Countermodel Comparison: “Treat the packet like a rigid rod”

If the packet were treated as a rigid rod, both energy and volume would scale by 1/γ = 0.8000 (E′_wrong = 0.800 J). The true energy factor is q = 0.5000 and the true volume factor is 1/q = 2.0000. At φ = 90° in K those differ from 1/γ by γ². At cos φ = β they do not.

Accepted snapshot

Relativistic light complex transformation factors compared to the naive material contraction countermodel.
Energy in K (E)1 J
Physical Energy in k (E′)0.5 J
Volume in K (V)1
Physical Volume in k (V′)2
Energy ratio E′/E (q)0.5
Volume ratio V′/V (1/q)2
Material volume factor 1/γ0.8
Lorentz factor γ1.25
Transformed angle in k (φ′)0 °
Countermodel E′ (1/γ)0.8 J (wrong model)
Countermodel V′ (1/γ)0.8 (wrong model)

Remarkably, the energy factor E′/E equals the Doppler frequency ratio ν′/ν = q across all angles and speeds. This exact proportionality between light energy and wave frequency holds invariantly for any bounded light packet under Lorentz transformations.

Not modeled: media and dispersion; quantum photon structure; finite pulse dispersion in dielectric; gravitational redshift; boundary diffraction at packet edges.

Worked case (readable without JavaScript)

Consider a spherical light complex of initial volume V = 1.0 m³ and total energy E = 1.0 J propagating along the x-axis (φ = 0°) in the stationary system K. An observer moves along the x-axis at speed v = 0.6c (β = 0.6, γ = 1.25).

The Doppler factor is q = γ(1 − β cos φ) = 1.25(1 − 0.6) = 0.5. Because the moving observer's simultaneous spatial plane cuts across a moving wave front, the volume of the complex in k transforms as:

VV=1q=1β21βcosφ=10.5=2.0    V=2.0 m3\frac{V'}{V} = \frac{1}{q} = \frac{\sqrt{1 - \beta^2}}{1 - \beta\cos\varphi} = \frac{1}{0.5} = 2.0\implies V' = 2.0\text{ m}^3

Meanwhile, the energy density transforms with the square of the amplitude ratio, $u'/u = q^2 = 0.25$. The total energy in the moving frame is:

E=uV=(uq2)(V/q)=uVq=Eq=0.5 JE' = u'V' = (u q^2)(V / q) = u V q = E q = 0.5\text{ J}

Notice the contrast with a rigid material body: a solid rod of volume V would undergo ordinary Lorentz contraction to V′rod = V/γ = 0.8 m³. Treating the light complex like that rod would give E′wrong = E/γ = 0.80 J, not 0.50 J. The case that isolates this mistake is a ray transverse in K (φ = 90°): q = γ = 1.25 while 1/γ = 0.80, so they differ by γ². A ray transverse in k (cos φ = β) gives q = 1/γ and cannot catch the mistake.

Einstein observed: “It is remarkable that the energy and the frequency of a light complex vary with the state of motion of the observer in accordance with the same law.”

EE=νν=γ(1βcosφ)\frac{E'}{E} = \frac{\nu'}{\nu} = \gamma(1 - \beta\cos\varphi)