Annus Mirabilis · Interactive critical edition in preparation
Photoelectric apparatus and stopping potential
Shine light on a metal and measure the fastest electrons it releases.
The photoelectric apparatus
Photoelectric apparatus laboratory
Static worked example
CurrentThese numbers match the current settings.
Model note
- Primary outputs incidentPower, frequency, workFunction, quantumEfficiency, collectorPotential: Host calculation (lq08.acceptedInputs). Owner lq08.acceptedInputs.
- Primary output quantumEnergy: Host calculation (photoelectric.quantumEnergy). Owner photoelectric.quantumEnergy.
- Primary output thresholdFrequency: Host calculation (photoelectric.thresholdFrequency). Owner photoelectric.thresholdFrequency.
- Primary output maxKineticEnergy: Host calculation (photoelectric.kMax). Owner photoelectric.kMax.
- Primary output stoppingPotentialMagnitude: Host calculation (photoelectric.stoppingPotentialMagnitude). Owner photoelectric.stoppingPotentialMagnitude.
- Primary output quantumRate: Host calculation (photoelectric.quantumRate). Owner photoelectric.quantumRate.
- Primary output emissionRate: Host calculation (photoelectric.emissionRate). Owner photoelectric.emissionRate.
- Primary output photocurrent: Host calculation (photoelectric.photocurrent). Owner photoelectric.photocurrent.
- Accepted input revision 1.
- Snapshot version 1.
- Not modeled: Real-material electron energy distributions and yields; Contact potentials and surface states; Space charge; Reflection losses; Emission angles; Multi-photon or thermionic emission; The timing of individual emissions; Energy transfer models beyond the declared complete or partial cases; Any claim that the moving marks depict photons.
Predict before the numbers
Make the lamp twice as bright without changing its frequency. What happens to the energy of the fastest electrons?
Predict before the numbers
Raise the frequency while keeping the lamp's power the same. What happens to the number of quanta arriving each second?
Predict before the numbers
Two different metals are lit by the same lamp. Plotted against frequency, are their stopping-potential lines parallel, crossing, or identical?
The result appears when you choose, say you have one in mind, or skip.
600.0 THz: one quantum carries hν = 2.48 eV
1.00 mW
2.515 × 1015 quanta arrive each second.
Experiment settings work function, quantum efficiency, collector potential
2.20 eV, a hypothetical metal unless a preset names one
Worked example: a quantum of 600 THz light carries 2.48 eV, more than the 2.2 eV work function, so the fastest electrons leave with 0.28 eV and a stopping potential of 0.28 V holds them back.
Where one quantum’s energy goes
hν = 2.481 eV, Φ = 2.20 eV , threshold ν0 = 532.0 THz
Stopping potential against frequency
In the model the slope is h/e = 4.136 × 10−15 V·s for every metal.
Millikan’s 1916 sodium measurements are not shown yet.
The six rows this laboratory used to plot could not be traced to Millikan's printed table. No image of the page was recorded, and the row for 312.6 nm gives a frequency 2.7 percent away from the speed of light divided by that wavelength while its voltage still sits on the fitted line, which is what a voltage computed from the frequency does and a reading from the page would not. They are withdrawn until his table is read from a scan of the journal.
R. A. Millikan, A Direct Photoelectric Determination of Planck's "h", Physical Review (2), 7 (3), 355–388 (1916).
Current against collector potential
Saturation current Isat = 40.30 μA
Values at these settings
| Quantity | Value |
|---|---|
| Energy of one quantum, hν | 2.481 eV |
| Threshold frequency, Φ/h | 532 THz |
| Largest electron energy, hν − Φ | 0.2814 eV |
| Stopping potential | 0.2814 V |
| Quanta arriving each second | 2.515 × 1015 per second |
| Electrons freed each second | 2.515 × 1014 per second |
| Current at this collector potential | 40.3 μA |
Light shining on a metal knocks electrons out of it. In this model, brighter light releases more of them each second but none faster, while light of a higher frequency makes the fastest ones faster, as Einstein expected if light gives up its energy in separate quanta.
Section 8 applies the light quantum to cathode rays produced by light. In the simplest picture, which Einstein says he will assume, one quantum gives its whole energy hν to one electron; the electron spends a work Φ, characteristic of the body, in leaving it, so the fastest electrons come out with kinetic energy hν − Φ. A body charged positive just enough to keep them all in, to the potential Vs, satisfies eVs = hν − Φ. Two consequences follow. Plotted against ν, Vs is a straight line whose slope, h/e, does not depend on the substance. And if each quantum acts independently of the rest, the intensity of the light changes how many electrons leave each second, not how fast they go. The defaults, 600 THz light at 1 mW on a hypothetical surface with Φ = 2.2 eV, give quanta of 2.48 eV, a threshold at 532 THz and a stopping potential of 0.281 V; with one quantum in ten releasing an electron, 2.52 × 1014 electrons leave each second, a current of 40.3 μA. Doubling the power doubles the current and leaves 0.281 V unchanged.
Start with one quantum. Its energy is hν, Planck's constant times the frequency: h = 6.626 × 10−34 J s and ν = 6.00 × 1014 Hz give hν = 3.976 × 10−19 J. An electronvolt, the energy an electron gains in falling through one volt, is 1.602 × 10−19 J, so hν = 3.976/1.602 = 2.48 eV. To leave the metal an electron must do the work Φ, here 2.2 eV. If the quantum gives all its energy to one electron at the surface, the most that electron can keep is 2.481 − 2.2 = 0.281 eV. To stop it, charge the metal positive: an electron climbing back against a potential V loses eV of energy, so it turns back once eV equals its kinetic energy, and the fastest one needs Vs = 0.281 V. That is the stopping potential. A quantum that carries less than Φ releases nothing, so the light must have hν at least Φ, or ν at least ν0 = Φ/h = (2.2 × 1.602 × 10−19)/(6.626 × 10−34) = 5.32 × 1014 Hz, which is 532 THz. Now the intensity. A power of 1 mW delivers 10−3 J each second; shared into quanta of 3.976 × 10−19 J, that is 10−3/(3.976 × 10−19) = 2.52 × 1015 quanta each second. If one in ten releases an electron, 2.52 × 1014 electrons leave each second, and since each carries 1.602 × 10−19 C the current is 2.52 × 1014 × 1.602 × 10−19 = 4.03 × 10−5 A, or 40.3 μA. Double the power to 2 mW and there are twice as many quanta, so twice the current, 80.6 μA; each quantum still carries 2.48 eV, so the fastest electron still needs 0.281 V to stop. Einstein's own check sets the work to nothing, Φ = 0, and takes ν = 1.03 × 1015 Hz, where the solar spectrum ends in the ultraviolet. Then eVs = hν gives 4.26 V with today's constants. He printed 4.3 V and said it agrees in order of magnitude with Lenard's results.
Einstein wrote the quantum's energy as (R/N)βν, with R the gas constant, N the number of molecules in a gram-molecule and β the constant in Wien's exponent, so (R/N)β is Planck's h. He wrote Π for the potential, ε for the electron's charge and P for the work, and also gave the law per gram-equivalent of charge, ΠE = Rβν − P′. He called complete transfer to one electron the simplest picture, and allowed that an electron might take up only part of a quantum, in which case ΠE + P′ ≤ Rβν. In 1905 the prediction was untested: Lenard had reported in 1902 that the electrons' speed does not depend on the intensity of the light, but nobody had yet measured the straight line Einstein predicted. Millikan did so in 1916, finding a slope that gave Planck's h to within about half a percent, while calling the theory by which Einstein had reached the equation untenable. The word photon is Lewis's, from 1926.
Einstein’s 1905 §8 check, by order of magnitude
What was neglected: Einstein sets P' = 0 as a deliberate neglect of escape work for order-of-magnitude comparison against Lenard's spark-potential observations, not as a physical prediction for a named metal.
What it is not: This is not a prediction for any named metal; any real substance has P' > 0, so its stopping potential at this frequency is lower by exactly the amount the work function contributes.
As printed: Π = Rβν / E = 4.34 V, “ca. 4,3 Volt”. Slope 4.212 × 10−15 V·s, against a modern h/e of 4.136 × 10−15 V·s.
At these settings: ν = 600.0 THz gives hν = 2.481 eV; with the hypothetical Φ = 2.20 eV the stopping potential is 0.281 V.
What this model leaves out
It follows Einstein’s 1905 rule that one absorbed quantum gives its energy to one electron, which spends Φ escaping. It does not model:
- Real-material electron energy distributions and yields
- Contact potentials and surface states
- Space charge
- Reflection losses
- Emission angles
- Multi-photon or thermionic emission
- The timing of individual emissions
- Energy transfer models beyond the declared complete or partial cases
- Any claim that the moving marks depict photons
The explanation
Full explanation
In this model brighter light releases more electrons each second but none faster, while light of a higher frequency makes the fastest ones faster. The stopping potential rises in a straight line with the frequency, as Einstein expected if light gives up its energy in separate quanta.
Show every step of the investigation
Change the intensity and then the frequency, and compare what each does to the current and to the stopping potential. Below the threshold frequency no electron is emitted, and the stopping potential is reported as not applicable rather than zero.
An explanatory model, not an observation of nature. This embed starts from the laboratory’s worked defaults, not a saved run. Presentation options change the surrounding guide, never the numerical inputs.