Annus Mirabilis · Interactive critical edition in preparation

The light clock and moving clocks

Compare what a travelling clock reads with the platform clocks it moves past.

Moving clocks

Static worked example

CurrentThese numbers match the current settings.

Choose a worldline
Clock speed (fraction of c)
0.6
Worldline
out and back
Coordinate duration
10 s

Worked example: a clock moving at 0.6c out and back: the platform clocks read 10 s while it reads 8 s.

The platform clocks read 10 s; the moving clock reads 8 s.Platform clocks, t = 10 sMoving clock, τ = 8 s
The moving clock's own time against the platform's coordinate time.
Proper time (τ)8 s
Coordinate time (t)10 s
τ / t0.8
Loss per second: the exact form beside the printed second-order approximation ½β². Neither stands in for the other.
Exact loss per second0.2
Printed second-order form (½β²)0.18
When the clocks meet again: the exact lag beside the printed approximation ½tβ², which is labelled as one.
Exact lag at reunion2 s
Printed approximation (½ t β²)1.8 s (approximation, not exact)
Each inertial frame reports the same dilation factor for the other clock's rate. Comparing clocks that are apart needs a stated simultaneity convention; only the reunion comparison above holds in every frame.
Dilation factor (γ)1.25
The light clock (supplemental illustration, offered after the measurement definitions: it illustrates dilation, it does not define it).
Proper tick (2L₀/c)2 s
Coordinate tick2.5 s

A clock losing exactly one second per day moves at β ≈ 0.00481124.

A clock that travels away and comes back reads less time than an identical clock that stayed put. At 60 percent of the speed of light, a trip that takes 10 seconds on the clock at home takes only 8 seconds on the traveller.

Section 4 takes a clock at rest at the origin of the moving system k and asks how fast it runs, judged from the resting system K. Its position is x = vt, and the transformation gives its reading as τ = t√(1 − v2/c2), so each second it falls behind by 1 − √(1 − v2/c2) seconds, or ½(v/c)2 to within terms of fourth order. Einstein draws the consequence: a clock carried from A to B and set beside one that stayed there lags by ½t(v/c)2, and so does a clock taken round a closed path back to its start. The instrument computes that reunion for an out-and-back trip or a circle at constant speed. At 0.6c over 10 s of the resting clock, the traveller reads 8 s: the exact loss is 0.2 s per second, 2 s in all, where the printed approximation gives 0.18 s per second, 1.8 s. A light clock with an arm of 1 light-second ticks every 2 s in its own frame and every 2.5 s as judged from K, the same factor 1.25. The comparison is of clock readings at a shared event; it is not what a camera would see.

Model: an ideal clock whose rate depends only on its instantaneous speed. Not modeled: gravitational time dilation, real clock mechanisms under acceleration, rotating-frame synchronization, the geoid's actual shape, atomic-clock physics, and clock noise.

The explanation

Full explanation

A clock moving at speed v falls behind the platform clocks by 1 − √(1 − v²/c²) seconds each second, which §4 prints to second order as ½(v/c)². A trip out and back, or round a circle, returns the clock to its start, where both clocks are read at one place and no simultaneity convention is needed.

Show every step of the investigation

Choose a worldline and a speed, and read the traveller's own time, the platform time and the lag when they meet again: at 0.6c over 10 s of platform time the traveller reads 8 s. Compare the exact loss per second with the printed approximation at low speed, then read the light clock's tick in each frame.

An explanatory model, not an observation of nature. This embed starts from the laboratory’s worked defaults, not a saved run. Presentation options change the surrounding guide, never the numerical inputs.