Annus Mirabilis · Interactive critical edition in preparation

Electric and magnetic frame change

Describe one field in two frames and compare what a test charge feels.

Electrodynamics §6

Electric and magnetic frame change

Static worked example

CurrentThese numbers match the current settings.

Model note
  • Primary outputs electricFieldStationary, electricFieldMoving, magneticFieldStationary, magneticFieldMoving: Host calculation (fields.transformSI). Owner fields.transformSI.
  • Primary outputs fieldInvariantEDotB, fieldInvariantE2MinusC2B2, fieldInvariantEDotBMoving, fieldInvariantE2MinusC2B2Moving: Host calculation (fields.fieldInvariants). Owner fields.fieldInvariants.
  • Primary output lorentzFactor: Host calculation (kinematics.gamma). Owner kinematics.gamma.
  • Primary outputs chargeVelocityStationary, chargeVelocityMoving: Host calculation (fields.transformVelocity3D). Owner fields.transformVelocity3D.
  • Primary outputs transverseForceLaboratory, transverseForceComoving, electricForceStationary, electricForceMoving, magneticForceStationary, magneticForceMoving: Host calculation (fields.lorentzForce). Owner fields.lorentzForce.
  • Primary outputs forceMovingFromFourForce, forceTransformationResidual, particleTimeJacobian: Host calculation (host:three-force-transform-v1). Owner host:three-force-transform-v1.
  • Accepted input revision 1.
  • Snapshot version 1.
  • Not modeled: field sources and currents; radiation and self-fields; radiation reaction; back-reaction on the field; media and polarization; nonuniform fields; accelerated observers.

Whether a field is electric, magnetic or both depends on who describes it. A field that is purely electric for one observer has a magnetic part for an observer moving past, and the two descriptions agree about what a charge in it does.

§6 applies the transformation of §3 to the Maxwell–Hertz equations for empty space and asks what fields must hold in the moving system k if the equations are to keep their form there. For a boost with speed v along x, the components along the motion are unchanged, X′ = X and L′ = L, while the transverse ones mix: Y′ = β(Y − (v/V)N) and N′ = β(N − (v/V)Y), and likewise for Z and M. Einstein's β is the modern γ, and V is the speed of light. The lab's default is a pure electric field of 1 V/m along y and a boost of 0.6c, so γ = 1.25. In k the electric field is 1.25 V/m, and a magnetic field of −2.50 × 10−9 T along z appears where there was none. A charge at rest in K feels 1.60 × 10−19 N; in k it moves at −0.6c through both fields and feels 1.28 × 10−19 N, the value in K divided by γ. §6 then states the result in two ways. The old manner: a charge moving in a field feels, besides the electric force, an electromotive force equal, to first order in v/V, to its velocity crossed with the magnetic force and divided by the speed of light. The new manner: the force on a moving charge is the electric force found by transforming the field to a frame in which the charge is at rest. Let the charge move with k and the lab shows that force, 2.00 × 10−19 N, all of it electric. The electromotive force becomes an auxiliary concept, and the asymmetry between magnet and conductor from the introduction disappears. The ledger also prints two combinations that the boost leaves unchanged, E·B = 0 and E² − c²B² = 1 (V/m)², as a check on the arithmetic; §6 does not use them.

Predict before the numbers

When a pure electric field in the y direction is described from a frame moving along x at 0.6c, what magnetic field appears?

Three relations the model could have

The result appears when you choose, say you have one in mind, or skip.

Set observer and fields
Description frame
Unit convention
Experiment settings the electric and magnetic field strengths

Changes here apply with Apply settings.

Worked example: seen from the frame moving at 0.6c, the electric field (0, 1, 0) V/m becomes (0, 1.25, 0) V/m and the magnetic field (0, 0, 0) T becomes (0, 0, −2.5 × 10⁻⁹) T.

Laboratory frame K, SI units

Fields in the laboratory frame KVector representation of electric field E, magnetic field B, and Lorentz force F under Lorentz transformation.xyE (1.00 V/m)F E² - c²B² = 1 | E·B = 0 | γ = 1.25

Transformation ledger

Comparison of electromagnetic field quantities across stationary (K) and moving (k) frames.
E (Stationary K)(0, 1, 0) V/m
E′ (Moving k)(0, 1.25, 0) V/m
B (Stationary K)(0, 0, 0) T
B′ (Moving k)(0, 0, −2.5017 × 10⁻⁹) T
Lorentz Factor γ1.25
Invariant E² − c²B²1 (V/m)²
Invariant E · B0 T·V/m
Laboratory force F(0, 1.6022 × 10⁻¹⁹, 0) N
Comoving force F′(0, 1.2817 × 10⁻¹⁹, 0) N

Not modeled: field sources and currents; radiation and self-fields; radiation reaction; back-reaction on the field; media and polarization; nonuniform fields; accelerated observers.

The explanation

Full explanation

Change the boost and watch the electric and magnetic components mix. The components differ from frame to frame, while the combinations E² − c²B² and E · B stay the same.

Show every step of the investigation

Start with a pure electric field, add a boost, and read the magnetic field that appears. Compare the transformed components with the two invariants, then place a test charge and compare the forces found in each frame.

An explanatory model, not an observation of nature. This embed starts from the laboratory’s worked defaults, not a saved run. Presentation options change the surrounding guide, never the numerical inputs.