Annus Mirabilis · Interactive critical edition in preparation
Moving mirror reflection and radiation pressure
Reflect light off a receding mirror and account for every joule.
Moving mirror reflection and radiation pressure
Moving mirror reflection and radiation pressure
Static worked example
CurrentThese numbers match the current settings.
Model note
- Primary outputs frequencyRatio, cosPhiReflected, phiReflectedDeg, amplitudeRatio, radiationPressure, radiationForce, incidentPower, reflectedPower, workRate, energyBalanceResidual: Host calculation (waves). Owner waves.
- Accepted input revision 1.
- Snapshot version 1.
- Not modeled: mirror mass and acceleration (infinite mass limit); finite mirror thickness and internal absorption; diffraction at mirror edges; quantum radiation pressure fluctuations; non-monochromatic wave packets.
Predict before the numbers
The mirror recedes at 0.6c and light hits it head-on. What fraction of the incident frequency returns?
The result appears when you choose, say you have one in mind, or skip.
Worked example: light meeting a mirror that moves at 0.6c, 0° from the normal, leaves at 180° with 0.25 of its frequency; of 1.2 × 10⁸ W arriving, 3 × 10⁷ W is reflected and 8.99 × 10⁷ W does work on the mirror.
Energy per second
At the mirror, in the laboratory frame (K)
- incident light
- reflected light, at a lower frequency
- work the light does pushing the mirror (P·v·Am)
- F, the radiation force on the mirror
Values at these settings
| Frequency ratio ν′′′/ν | 0.25 |
|---|---|
| Reflection cosine cos(φ′′′) | −1 |
| Reflection angle φ′′′ | 180 ° |
| Amplitude ratio A′′′/A | 0.25 |
| Radiation pressure P | 0.5 Pa |
| Radiation force F | 0.5 N |
| Incident power | 1.1992 × 108 W |
| Reflected power | 2.9979 × 107 W |
| Work done on the mirror, P·v·Am | 8.9938 × 107 W |
| Energy balance residual | 0 W |
At normal incidence with a receding mirror (β = 0.6), the incident power is 0.4 IAm, the reflected power 0.1 IAm, and the mirror receives mechanical work at the rate 0.3 IAm. Energy is conserved exactly, with zero residual.
Light bouncing off a mirror that moves away comes back redder and weaker, and pushes the mirror less hard than it pushes a mirror at rest. The energy the light loses is exactly the work it does in pushing the mirror along.
The second half of §8 lets the plane waves of §7 fall on a perfectly reflecting mirror that moves with the system k. Einstein transforms the incident light into k, where the mirror is at rest and reflection is ordinary, and transforms the reflected light back to K. For normal incidence on a mirror receding at 0.6c, the reflected light has a quarter of the incident frequency and a quarter of the amplitude, so a sixteenth of the energy per unit volume. The energy principle then gives the pressure: the energy arriving at the mirror each second, less the energy leaving it, is the work the light does in pushing the mirror, P·v, and §8 finds P = 2(A²/8π)(cos φ − v/V)²/(1 − (v/V)²). With 1 J/m³ of light that is 0.5 Pa, against 2 Pa on a mirror at rest; to first order in v/V it is 2(A²/8π) cos² φ, which Einstein notes agrees with experience and with other theories. On a 1 m² mirror, 1.199 × 108 W arrives, 2.998 × 107 W leaves, and the other 8.994 × 107 W is the work done on the mirror, so the ledger balances. Drive the mirror toward the light at 0.6c and everything reverses: four times the frequency, 8 Pa, and the mirror does work on the light. At 30° the reflected ray still leans slightly forward, cos φ′′′ = +0.069, yet it moves along the mirror's direction at only 0.069c while the mirror moves at 0.6c, so the two separate. At oblique incidence the light's speed toward the mirror is c cos φ; at 60° and 0.6c that is 0.5c, less than the mirror's speed, so the light never catches it, and the lab says so instead of computing. In the mirror's own frame no work is done, and the reflected power equals the incident power.
Take normal incidence on a mirror receding at β = 0.6. First the frequency. In the mirror's frame the incident light is shifted by §7's factor √((1 − β)/(1 + β)) = √(0.4/1.6) = 0.5. The mirror, at rest there, sends it back at that frequency. Seen from K, the reflected light comes from a mirror moving away, so it is lowered by the same factor again, and 0.5 × 0.5 = 0.25. §8's general formula, A′′′/A = (1 − 2β cos φ + β²)/(1 − β²), gives the same at φ = 0: (1 − 1.2 + 0.36)/0.64 = 0.16/0.64 = 0.25, and the amplitude falls by that factor as well. Energy per unit volume goes as the amplitude squared, so it falls to 0.25² = 0.0625 J/m³. Now the energy per second on 1 m². The incident light fills 1 J/m³ and moves toward the mirror at c, but the mirror moves away at v, so the light reaches it at the relative rate c − v = 0.4c, and 1 × 0.4 × 2.998 × 108 = 1.199 × 108 J arrive each second. The reflected light, at 0.0625 J/m³, leaves at c while the mirror follows at v, so the region it fills grows by c + v = 1.6c each second: 0.0625 × 1.6c = 0.1c = 2.998 × 107 W. The difference, 0.3c = 8.994 × 107 W, has gone into the mirror as work. Work per second is force times velocity, so the force on each square metre is P = 0.3c/0.6c = 0.5 Pa. §8's formula agrees: 2 × 1 × (1 − 0.6)²/(1 − 0.36) = 2 × 0.16/0.64 = 0.5 Pa. A mirror at rest would feel 2 × 1 = 2 Pa, twice the energy per unit volume, because the light's momentum is reversed. Approaching at 0.6c, the same steps give a frequency ratio of 1.6/0.4 = 4, a pressure of 2 × 1.6²/0.64 = 8 Pa, 1.6c = 4.797 × 108 W arriving, 6.4c = 1.919 × 109 W leaving, and a work rate of −1.439 × 109 W: the mirror now does work on the light. At φ = 30°, cos φ = 0.866, and §8's reflection law gives cos φ′′′ = −((1 + 0.36) × 0.866 − 1.2)/(1 − 1.2 × 0.866 + 0.36) = 0.0222/0.3208 = +0.069, so φ′′′ = 86.0°: the reflected ray still has a small component along the mirror's motion. It separates anyway, because that component carries it along at 0.069c, about 2.1 × 107 m/s, while the mirror moves at 0.6c, 1.8 × 108 m/s. There the pressure is 0.221 Pa, and 7.975 × 107 W in, 3.997 × 107 W out and 3.978 × 107 W of work still balance. In the mirror's own frame the mirror does not move, so no work is done, and incident and reflected powers are equal; the difference in K is entirely the work of a moving force.
§8 writes the energy per unit volume as A²/8π and the speed of light as V, and marks the reflected quantities with triple primes, A′′′, φ′′′ and ν′′′. Its first-order result, 2(A²/8π) cos² φ, is the pressure Maxwell's theory gave for a mirror at rest, which Bartoli had also argued for from thermodynamics; Lebedev, and independently Nichols and Hull, measured light pressure in 1901. The exact formula for a moving mirror, and the energy bookkeeping that yields it, are what §8 adds. Its closing claim, that the optics of moving bodies reduces to the optics of bodies at rest by a change of frame, states the program of the whole paper.
Not modeled: mirror mass and acceleration (infinite mass limit); finite mirror thickness and internal absorption; diffraction at mirror edges; quantum radiation pressure fluctuations; non-monochromatic wave packets.
The explanation
Full explanation
The reflected light has lower frequency and amplitude, the mirror feels a pressure, and the power that arrives minus the power that leaves is the work done on the mirror. At 0.6c and normal incidence the frequency returns at a quarter, and three quarters of the arriving power becomes work.
Show every step of the investigation
Transform into the mirror's frame, reflect there, and transform back. Read the frequency, angle and amplitude ratios, then the pressure and the energy ledger; where the light is too oblique to catch the mirror, the lab says so.
An explanatory model, not an observation of nature. This embed starts from the laboratory’s worked defaults, not a saved run. Presentation options change the surrounding guide, never the numerical inputs.