Read · Special relativity: from clock operations to electrodynamics

§3 · deriving and inverting the coordinate map

Follow the introduction and all ten sections, including field transformations, finite light complexes, moving mirrors, charge-current transformations, and the electron-force conventions.

Newly authored explanatory preview in modern notation, with editorial and physics review pending. Both the kinematic and electrodynamic halves are treated, but this is not a German transcription, an aligned translation, or a complete critical edition. The source paragraphs, footnotes, acknowledgment, and date-lines are not claimed to be fully represented or reviewed here. Headings and argument units are editorial.

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§3 · deriving and inverting the coordinate map

derivation · Within the stated model

Light constraints leave a scale to determine

What map can respect both light directions?

The moving origin follows x = vt, so write x′ = a(v)(x − vt). Requiring x′ = ct′ on x = ct and x′ = −ct′ on x = −ct fixes the time combination: t′ = a(v)(t − vx/c²). An overall scale a(v) remains.

x=a(v)(xvt),t=a(v)(tvxc2)x'=a(v)(x-vt),\qquad t'=a(v)\left(t-\frac{vx}{c^2}\right)

The light constraints give a common coefficient multiplying x minus vt and t minus vx over c squared.

Applying the inverse with speed −v gives a(v)a(−v)(1 − v²/c²) = 1. Isotropy identifies a(v) with a(−v). Continuity from a(0) = 1 selects the positive square root.

γ=11v2/c2,x=γ(xvt),t=γ(tvxc2)\gamma=\frac{1}{\sqrt{1-v^2/c^2}},\qquad x'=\gamma(x-vt),\quad t'=\gamma\left(t-\frac{vx}{c^2}\right)

The Lorentz factor is one over the square root of one minus v squared over c squared, giving the standard space and time transformation.

Show every step here: Light constraints leave a scale to determine
  1. Use the moving origin to determine the combination x − vt.
  2. Substitute both right-moving and left-moving light paths into the linear time map.
  3. Solve the resulting coefficient constraints without setting the scale by hand.
  4. Compose with the inverse transformation.
  5. Use isotropy to equate the positive-speed and negative-speed scales.
  6. Choose the identity-connected positive solution, requiring |v| less than c.
Assumptions and limits: Light constraints leave a scale to determine

Assumed here

  • Use aligned inertial axes and coincident origins at zero time.
  • Assume homogeneous space and time so the coordinate map is linear.
  • Use the postulates together with reciprocity, spatial isotropy, and continuity at zero speed.

What this does not establish

  • Preserving a light ray alone does not uniquely fix all transformation coefficients.
  • A spacetime interval or matrix is a later verification aid, not an unannounced 1905 premise.

Earlier step: Time at a distant clock is an operationOne apparatus, two descriptions

Source context: German source · English · Interlinear gloss · Facsimile

derivation · Within the stated model

The sideways step needs its own condition

Why do the transverse coordinates stay unchanged?

Write y′ = b(v)y for a transverse axis. On a ray with x = 0, y = ct, the already determined longitudinal map gives x′ = −γvt and t′ = γt. Requiring the transformed ray’s speed to be c gives γ²v² + b²c² = γ²c², hence b² = 1.

The positive, identity-connected choice gives y′ = y and likewise z′ = z. The inverse map replaces v with −v and exchanges primed and unprimed quantities.

x=γ(x+vt),t=γ(t+vxc2)x=\gamma(x'+vt'),\qquad t=\gamma\left(t'+\frac{vx'}{c^2}\right)

The inverse transformation uses plus v and exchanges the two frames.

At v = 0.6c, γ = 1.25. In units where c = 1, the event (t, x) = (2, 1) becomes (1.75, −0.25); the inverse returns (2, 1). SR-04 can check the same map from either direction.

Show every step here: The sideways step needs its own condition
  1. Introduce an independent transverse scale rather than assuming it is one.
  2. Transform a ray originally perpendicular to the boost.
  3. Require the full transformed speed, including its longitudinal component, to equal c.
  4. Solve for the transverse scale and select the positive identity-connected branch.
  5. Apply the inverse to a complete event, not just its spatial coordinate.
Assumptions and limits: The sideways step needs its own condition

Assumed here

  • Use the scale fixed in the longitudinal transformation.
  • Light has the same speed in all spatial directions, not only along x.

What this does not establish

  • Checking a single axial ray cannot test transverse normalization.
  • Matrix determinants and interval checks verify this result but do not replace its stated physical premises.

Earlier step: Light constraints leave a scale to determine

Source context: German source · English · Interlinear gloss · Facsimile

References and source status

Newly authored explanatory preview in modern notation, with editorial and physics review pending. Both the kinematic and electrodynamic halves are treated, but this is not a German transcription, an aligned translation, or a complete critical edition. The source paragraphs, footnotes, acknowledgment, and date-lines are not claimed to be fully represented or reviewed here. Headings and argument units are editorial.

A. Einstein, Zur Elektrodynamik bewegter Körper. Annalen der Physik (4), 17, 891–921 (1905).

A. Einstein, Does the inertia of a body depend upon its energy content?. Annalen der Physik (4), 18, 639–641 (1905). External 1923 Perrett–Jeffery translation, electronically transcribed by John Walker; its notation was modernized. A reference for this explanatory preview, not this edition’s reviewed translation or pinned facsimile.

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