Annus Mirabilis · Interactive critical edition in preparation
Matching the radiation and gas entropy coefficients
Compare the volume dependence of two entropy expressions.
The move in §6
Matching the entropy laws to find the light quantum
Static worked example
CurrentThese numbers match the current settings.
Model note
- Primary outputs radiationEnergy, frequency, volumeRatio, independentPointCount: Host calculation (lq06.acceptedInputs). Owner lq06.acceptedInputs.
- Primary outputs effectiveIndependentCount, quantumEnergy, quantumEnergyEv, meanQuantumEnergyWien, meanQuantumEnergyWienEv, moleculeMeanKineticEnergyEv, meanEnergyRatio, ratioAt600THz: Host calculation (radiation.quanta). Owner radiation.quanta.
- Primary outputs radiationEntropy, entropyVolumeCoefficient: Host calculation (radiation.entropy). Owner radiation.entropy.
- Primary outputs gasEntropy, gasEntropyVolumeCoefficient: Host calculation (radiation.configurations). Owner radiation.configurations.
- Primary output correspondenceVerdict: Host calculation (lq06.correspondence). Owner lq06.correspondence.
- Accepted input revision 1.
- Snapshot version 1.
- Not modeled: Radiation outside the Wien regime; Mechanism of emission and absorption (reserved for §§7–9); Cavity wall dynamics and boundary interactions; Wave interference patterns inside the volume.
Predict before the numbers
The radiation's entropy is S − S₀ = (R/N) ln[(V/V₀)NE/(Rβν)], and a gas of n molecules has S − S₀ = (R/N) n ln(V/V₀). Which expression plays the part of n?
Predict before the numbers
Over a Wien spectrum, how does the mean energy of a light quantum compare with a gas molecule's mean kinetic energy at the same temperature?
The result appears when you choose, say you have one in mind, or skip.
600.0 THz: each quantum carries 2.481 eV
Experiment settings volume ratio, the comparison gas, temperature
Side-by-side entropy volume laws (§6, the move)
V/V₀ = 0.50Wien monochromatic radiation (§4)
E = 9.056 nJ, ν = 600.0 THz
S − S₀ = (E/βν) · ln(V/V₀)
Written with Boltzmann’s constant, k = R/N:
= (R/N) · [ ? ] · ln(V/V₀)
Ideal gas / solute molecules (§5)
n = 10 independent particles
S − S₀ = (R/N) · ln W
Independent positions, W = (V/V₀)n:
= (R/N) · [ n ] · ln(V/V₀)
Which expression goes in the bracket? Choose one in the controls. Coefficients of ln(V/V₀) now: radiation 3.145 × 10−13 J/K, gas 1.381 × 10−22 J/K.
Wien spectrum mean quantum energy against a gas molecule’s kinetic energy (§6)
T = 3000 KIntegrating over a full Wien spectrum, the average energy of a light quantum is exactly twice the average translational kinetic energy of a gas molecule (at 600 THz, monochromatic h·ν is 3.20× this mean quantum energy):
Mean energy of a light quantum in a Wien spectrum, ⟨ε⟩ = 3kBT
Mean translational kinetic energy of a gas molecule, ⟨Ekin⟩ = (3/2)kBT
Ratio of the two: 2.0 : 1
The three logical roles of the match
1. Derivation (algebra)
The Wien radiation entropy and the Boltzmann gas entropy have the same form exactly when n = NE/(Rβν) = E/(hν).
2. Heuristic inference
Monochromatic radiation of low density, in the Wien regime, behaves thermodynamically as though it consisted of independent energy quanta of size hν.
3. Further hypothesis
Are the production of light (Stokes's rule, §7) and its transformation (the photoelectric effect, §8; ionization, §9) also exchanges in amounts of hν?
Values at these settings
| Quantity | Value |
|---|---|
| Radiation energy E | 9.056 nJ |
| Frequency ν | 600.0 THz |
| Volume ratio V/V₀ | 0.5 |
| Number of independent quanta, neff | 2.2778 × 1010 |
| Energy of each, hν | 3.9756 × 10−19 J |
| Energy of each, hν | 2.4814 eV |
| Radiation: coefficient of ln(V/V₀) | 3.1448 × 10−13 J/K |
| Gas: coefficient of ln(V/V₀) | 1.3806 × 10−22 J/K |
| Radiation: entropy change | −2.1798 × 10−13 J/K |
| Gas: entropy change | −9.5699 × 10−23 J/K |
| Mean quantum energy over a Wien spectrum, 3kBT | 0.77556 eV |
| Mean kinetic energy of a gas molecule, (3/2)kBT | 0.38778 eV |
| Ratio of the two | 2 |
When faint light of one colour is squeezed into half the room, its entropy falls by the same rule as a gas of independent particles does. Matching the two rules says how many particles the light would have to contain, and so how much energy each one carries, an amount set by the colour of the light.
Section 4 found that radiation of energy E in a narrow band at frequency ν, where Wien's law holds, changes its entropy with volume as S − S0 = (E/βν) ln(v/v0). Section 5 used Boltzmann's principle, S − S0 = (R/N) ln W: for n independent moving points the probability that all of them are in a part v of the volume v0 is W = (v/v0)n, so S − S0 = (R/N) n ln(v/v0). Section 6 writes the radiation result in the same form, S − S0 = (R/N) ln[(v/v0)(N/R)(E/βν)], and reads off the probability that all the radiation energy is in v. The exponent plays the part of n: the energy behaves as if it consisted of n = NE/(Rβν) independent quanta, each of size Rβν/N, which is hν. At the defaults, 9.06 × 10−9 J at 600 THz, that is 2.28 × 1010 quanta of 2.48 eV. Halving the volume lowers the radiation's entropy by 2.18 × 10−13 J/K, as it would for a gas of that many points; the instrument's gas of 10 points loses 9.57 × 10−23 J/K. Einstein then compared the mean quantum of a whole Wien spectrum, 3(R/N)T, with a molecule's mean kinetic energy, (3/2)(R/N)T: at 3000 K, 0.776 eV against 0.388 eV, a factor of 2.
Boltzmann's principle ties entropy to probability: S − S0 = (R/N) ln W, where R/N, the gas constant divided by the number of molecules in a mole, is 1.381 × 10−23 J/K. Take n independent points moving about a box of volume v0. The chance that one of them is, at a given moment, in a part v of the box is v/v0. Because they move independently, the chance that all n are there together is the product, (v/v0)n. With 10 points and half the box, that is (1/2)10 = 1/1024. The entropy difference is then (R/N) ln[(v/v0)n] = (R/N) n ln(v/v0) = 1.381 × 10−23 × 10 × ln 0.5 = −9.57 × 10−23 J/K. Now the radiation. Section 4 gives S − S0 = (E/βν) ln(v/v0). Pull R/N out in front, E/βν = (R/N) × (N/R)(E/βν), and use the rule that a number times a logarithm is the logarithm of a power: S − S0 = (R/N) ln[(v/v0)(N/R)(E/βν)]. Set this beside the gas. The two have the same form if n = (N/R)(E/βν). Divide the energy by that count to find the energy of one part: E/n = Rβν/N. With today's constants Rβ/N is Planck's h, 6.626 × 10−34 J s, so each part carries hν = 6.626 × 10−34 × 6.00 × 1014 = 3.976 × 10−19 J, or 2.48 eV. The defaults hold E = 9.056 × 10−9 J, so n = 9.056 × 10−9/(3.976 × 10−19) = 2.28 × 1010. The radiation's coefficient E/βν is n times R/N, 2.28 × 1010 × 1.381 × 10−23 = 3.145 × 10−13 J/K, and halving the volume changes the entropy by 3.145 × 10−13 × ln 0.5 = −2.18 × 10−13 J/K. The probability that all that light is in one half at once is 1/2 raised to the power 2.28 × 1010, too small to write out. Last, the mean quantum. Over a whole Wien spectrum at temperature T, the energy per unit frequency is αν3e−βν/T, and the number of quanta per unit frequency is that divided by Rβν/N; the ratio of the two integrals is 3(R/N)T. At 3000 K that is 3 × 1.381 × 10−23 × 3000 = 1.243 × 10−19 J, or 0.776 eV, twice a gas molecule's (3/2)(R/N)T = 0.388 eV. A 600 THz quantum, at 2.48 eV, is 3.20 times the mean.
Einstein wrote lg for the natural logarithm and v for the volume, and he never wrote h: the quantum is Rβν/N, built from the values of R, N and β that Planck had used. With R = 8.31 × 107 erg per mole and kelvin, N = 6.17 × 1023 and β = 4.866 × 10−11 s K, Rβ/N comes to 6.55 × 10−27 erg s, about 1.1 percent below the modern h; the paper does not print the product. He stated the conclusion with its limits: monochromatic radiation of low density, within the range of Wien's formula, behaves thermodynamically as if it consisted of mutually independent quanta. Planck had introduced energy elements hν in 1900 for the resonators of his cavity, not for the radiation itself. The comparison of 3(R/N)T with (3/2)(R/N)T is Einstein's own, at the end of Section 6.
What this model leaves out
- Radiation outside the Wien regime
- Mechanism of emission and absorption (reserved for §§7–9)
- Cavity wall dynamics and boundary interactions
- Wave interference patterns inside the volume
The rule this laboratory evaluates
From src/physics/reference/radiation/quanta.ts, the audited TypeScript reference evaluator.
// Paper 1, §6: matching the entropy coefficients
// Radiation entropy: S - S_0 = (E / (beta * nu)) * ln(V / V_0)
// Boltzmann gas entropy: S - S_0 = (R / N) * n * ln(V / V_0)
//
// Equating the exponents in W = (V / V_0)^n:
// n_eff = (N / R) * (E / (beta * nu)) = E / (h * nu)
// Energy per quantum: epsilon = E / n_eff = (R * beta * nu) / N = h * nu
//
// Mean quantum energy over a Wien spectrum:
// <epsilon> = 3 * (R / N) * T = 3 * k_B * T, twice a molecule's 1.5 * k_B * TThe explanation
Full explanation
Change the radiation energy or frequency and inspect the coefficient match. Keep the mathematical identity separate from the physical hypothesis suggested by the analogy.
Show every step of the investigation
Inspect the radiation coefficient, the independent-particle coefficient, and the effective count that makes them agree. Check the constant set and the stated Wien-regime limitation before carrying the result into emission or absorption.
An explanatory model, not an observation of nature. This embed starts from the laboratory’s worked defaults, not a saved run. Presentation options change the surrounding guide, never the numerical inputs.