Annus Mirabilis · Interactive critical edition in preparation

Rod measurement and simultaneity

Measure a moving rod two ways and compare the answers.

An executable laboratory

Rod measurement, simultaneity, and causal order laboratory

Static worked example

The rod's length in the two frames

The rod is at rest in frame k, the moving frame, and frame K, the platform, measures it, at v = 0.60c. A length is the distance between the two ends read at one time of the measuring frame: coordinate geometry, not what a camera sees.

The two readings are Δx = 10.00 ls and cΔt = 0.00 ls apart in frame K. They are two marks on the platform, not the rod's ends, and simultaneous in frame K, so 10.00 ls is the distance between them there, not the rod's length. The rod itself, its ends read at one time of frame K, is 8.00 ls long there.

Frame K, the platform: 8.00 ls, L₀/γ

Frame k, moving at 0.60c: 10.00 ls, the proper length L₀

Spacetime event diagram of the two end readings

Light lines run at 45°. The moving frame's axes x′ and ct′ tilt toward them by arctan(v/c). Here γ = 1.25 and L₀ = 10.0 ls.

xctx′ct′E₁E₂

Axes in light-seconds. E₁ is at the origin in both frames. E₂ is at (x, ct) = (10.0, 0.0) in frame K and (x′, ct′) = (12.5, -7.5) in frame k.

A moving sphere measured as an ellipsoid (§4)

A sphere of radius R at rest in k, measured from K at one instant of K, has axes R/γ, R and R, that is R√(1 − v²/c²), R and R.

At v = 0.60c the measured axes are 0.80 ls along the motion (the horizontal line), and 1.00 ls and 1.00 ls across it. The dashed circle is the sphere at rest.

Predict before the numbers

At v = 0.6c, two events that mark the ends of a moving 10-ls rod are measured simultaneously in platform frame K (dt = 0, dx = 8 ls). What is their time separation dt' in the rod's rest frame k?

Three relations the model could have

Predict before the numbers

If two events have a timelike separation (s² < 0, so a signal slower than light could connect them), what happens to their time order when viewed from a frame moving at 0.95c?

Three relations the model could have

The result appears when you choose, say you have one in mind, or skip.

Try
Experiment settings speed, frames, rod length, sphere radius, event pair
Frames, speed and sizes
0.60 c
10.0 ls
1.0 ls

Worked example: the two readings are 10 ls and cΔt = 0 ls apart in frame K. They are two marks on the platform, not the rod's ends, and simultaneous in frame K, so 10.00 ls is the distance between them there, not the rod's length. The rod itself, its ends read at one time of frame K, is 8.00 ls long there.

Two flashes that happen at the same moment for one observer happen at different moments for an observer moving past. So a moving rod, whose two ends have to be marked at the same moment to measure it, comes out shorter than the same rod measured at rest.

Section 1 defines when two distant clocks agree: light sent from A to B and reflected back must take as long going as returning. Section 2 applies that test to clocks on the ends of a rod moving at speed v, set to agree with the clocks of the resting system K. Seen from K, the light gains on the receding end B at c − v and meets the approaching end A at c + v, so tB − tA = rAB/(c − v) and t′A − tB = rAB/(c + v). The two times differ, so observers riding with the rod find the clocks out of step, while observers in K call them synchronous. Section 4 turns this into geometry: a sphere of radius R at rest in the moving system k, located at one time of K, is an ellipsoid with axes R√(1 − v2/c2), R and R. The instrument measures in light-seconds with c = 1. At v = 0.6c the factor √(1 − v2/c2) is 0.8, a rod 10 light-seconds long at rest in k measures 8 light-seconds in K, and two events 10 light-seconds apart at one time of K are 7.5 s apart in k.

Spacetime event coordinates and invariant interval

FrameΔt (s)Δx (ls)Simultaneitys² = Δx² − c²Δt² (ls²)Causal order
K (Platform)010Simultaneous100Spacelike
k (Moving)−7.512.5Second event earlier100Spacelike

Could one of these events have caused the other? No. Not even light can get from one event to the other in the time between them, so nothing done at one can affect the other, and observers moving differently can disagree about which came first.

Values at these settings

QuantityValue
Distance between the two readings in K, Δx (platform marks, not the rod)10 ls
Time between the events in K, Δt0 s
Distance between the two readings in k, Δx′ (platform marks, not the rod)12.5 ls
Time between the events in k, Δt′−7.5 s
Their time order in Ksimultaneous
Their time order in ksecond event earlier
Distance between the two readings at one time of frame K (platform marks, not the rod)10 ls
The rod's length in K, its ends read at one time of K8 ls
The rod's length in k, its ends read at one time of k10 ls
Are the two readings the rod's ends?no, they are not the rod's ends
Interval, s² = Δx² − c²Δt²100 ls²
Kind of separationspacelike
Lorentz factor, γ1.25
Sphere measured along the motion0.8 ls
Sphere measured across the motion (y)1 ls
Sphere measured across the motion (z)1 ls

What this model leaves out

It applies exact special-relativistic coordinate transformations, coordinate length measurements and invariant intervals between inertial frames. It does not model:

  • Optical camera image appearance (Terrell-Penrose rotation and light-travel-time distortion), which differs from coordinate measurement at a single instant.
  • Accelerating reference frames, Rindler horizons, or Thomas precession.
  • Internal stress, elasticity, Born rigidity breakdown, or relativistic wave propagation during rod acceleration.
  • Gravitational time dilation or spacetime curvature (general relativity).
  • Quantum uncertainty or field fluctuations at Planck-scale event intervals.
  • Superluminal observers (|v| ≥ c) or tachyonic coordinate frames.

The explanation

Full explanation

Lay a rule alongside the rod while riding with it, or mark where its ends are at one time of the resting system. The two operations give different lengths, and the lab shows which clocks decide what counts as one time.

Show every step of the investigation

Set the rod's speed and read the length each operation finds. Then follow the light signals that riders use to test the clocks at the rod's ends, and see why clocks in step for the resting system are out of step for them.

An explanatory model, not an observation of nature. This embed starts from the laboratory’s worked defaults, not a saved run. Presentation options change the surrounding guide, never the numerical inputs.