brownian motion
The equation explained
In wordsThe osmotic pressure times the part of the liquid's volume that holds the solution equals the gas constant times the absolute temperature times the number of gram-molecules dissolved.OverviewA dissolved substance, held in part of a liquid by a wall that lets only the solvent through, presses on that wall as a gas would: pressure times that volume equals R times the temperature times the gram-molecules dissolved. The paper states it for a non-electrolyte, when the volume per gram-molecule is large enough.Full explanationThe paper sets up the case it will compare with suspended particles. In a part of a liquid, gram-molecules of a non-electrolyte are dissolved, and a wall that lets the solvent through but not the dissolved substance separates from pure solvent. The wall then feels the osmotic pressure , and for large enough values of it satisfies , with the gas constant and the absolute temperature. That is the form of the gas law for gram-molecules, and the paper states it without derivation, as known. Its two conditions matter: a non-electrolyte, and a dilute solution, since large means much volume for each gram-molecule dissolved. The next display asks what the same wall feels when the part holds suspended bodies instead.Every stepThe law the paper states for gram-molecules of a non-electrolyte dissolved in the part , when is large enough. It is not derived in the paper.Divide both sides by . The pressure grows with the gram-molecules dissolved per unit of that volume, and with the absolute temperature.The same law with the volume per gram-molecule dissolved, , in the denominator. The paper asks for to be large enough: the law holds for a dilute solution, where the pressure is correspondingly small. What it counts is gram-molecules; the kind of dissolved substance does not enter.Historian's marginThe law is van 't Hoff's (Z. physik. Chem. 1, 1887, 481). He printed it in his own letters as ‘PV = RT’ (p. 491), valid for solutions with the restriction that holds for gases too: the dilution must be large enough. Most salts, and the strong acids and bases, give a larger pressure in water, by a factor he writes i, which he ascribed on Arrhenius's suggestion to a splitting into ions (p. 501). The paper names neither him nor his paper, and asks for the same two conditions: a non-electrolyte, and large enough .Also