light quanta

The equation explained

α=6,10⋅10−56,\alpha = 6{,}10 \cdot 10^{-56},
In wordsThe constant α of Planck's formula is 6.10 × 10⁻⁵⁶, as the paper prints it.OverviewThe first constant of Planck's formula, with the value the paper prints. It sets the height of the whole spectrum, and with β it will give the number of molecules in a gram-equivalent.Full explanationThe paper prints the two constants of Planck's formula on lines of their own, without units. α\alpha multiplies ν3\nu^3 in the numerator of Planck's formula, so it sets the height of the whole spectrum. The paper's argument uses it only through the ratio αβ\frac{\alpha}{\beta}, the coefficient of the long-wave form of the formula, from which it finds NN.Every stepα=6,10⋅10−56\alpha = 6{,}10 \cdot 10^{-56}The value as the edition reads it on p. 136, with the German decimal comma.αβ\frac{\alpha}{\beta}Where it acts: the paper uses α\alpha only through this ratio, the coefficient of the long-wave form ϱν=αβν2T\varrho_\nu = \frac{\alpha}{\beta} \nu^2 T.Historian's marginAs the edition reads the plate of p. 136, the exponent of α is −56. With the paper's β and the usual values of the time for R and L, which it does not print, the formula for N gives the printed 6.17 × 10²³ only with α = 6.10 × 10⁻⁵⁷; with −56 it gives a tenth of that. The provenance receipt records the plate reading, from a single witness, as watch-alpha-exponent (docs/provenance/ap-17-132.md), and the edition's historical constant set uses 10⁻⁵⁷ (content/quantities/constant-sets/einstein-1905-light-quanta-printed.yaml, cross-referenced there to the Collected Papers, vol. 2, doc. 14, p. 154).Also

Read it in the paper