special relativity
The equation explained
In wordsThe speed of the moving system plus the speed of a third system relative to it, divided by one plus their product over the square of the speed of light.OverviewCarry out the transformation of § 3 twice over and the result is a single transformation of the same kind, with this one speed in place of the original. Composing two of these transformations never leads outside the family.Full explanationThe formula for in the case of equal directions can also be had by composing two transformations. Beside the systems and of § 3 the paper introduces a third, , moving parallel to with its origin travelling along the Ξ-axis at the speed . The equations between and the corresponding quantities of then differ from those found in § 3 only in that this quantity stands in the place of . Two readings of that: it is a second derivation of the addition theorem, from the structure of the transformations rather than from a moving point; and it says that these parallel transformations form a group, which the paper notes on the next page with the remark that this is as it must be. Being a group is the guarantee that the theory gives one answer: a chain of transformations can be carried out in any grouping, and the family of admissible descriptions is closed.Every stepThe printed quantity: the composition of the two speeds, in the same form the addition theorem gave.The transformation of § 3 from the stationary system to , the first of the two to be applied.Its factor, which is fixed by the speed appearing in the transformation and by nothing else.What the two transformations together come to: equations of exactly the form found in § 3, with this speed wherever stood. So the composition of two such transformations is again one of them.Also